https://emily.shillest.net/ayaya/index.php?マニュアル/関数/LSO
LSO
LSO()
request { _i = foo LSO } foo { "earth" "moon" "sun" }
If "sun" is assigned to _i, the LSO is 2. This works for all cases where a choice is made regardless of the means. Therefore, it is meaningless unless the value is obtained immediately after the relevant process is completed.
request { { "This is a "+ANY("pen", "pencil", "eraser")+"." } res = LSO }
If you are trying to get the selection result of ANY, this code is wrong. An LSO in this position will get the selection result of {}. Therefore, res will always be 0. The following modification will make it work as intended.
request { { "This is a "+ANY("pen", "pencil", "eraser") + "." res = LSO } }
If an output determinant is present, LSO will work on all possible combinations.
request { { "1" "2" "3" -- "A" "B" } _i = LSO }
For example, the {} part in the above function outputs one of the following.
"1A" "2A" "3A" "1B" "2B" "3B"
The range of LSO values also matches this, from 0-5. The values match the list above.
Last modified on: 2008-04-08 (Tuesday) 22:29:55
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